PHP Code - Print Filename Under Image

JediMaster · 24-08-2010, 17:14

I have seen this Script http://www.devtek.org/tutorials/image_gallery.php & it works great for my needs. Display images (Thumbnails) in a GRID. I've edited it to REMOVE Click on Image to see Full Image (as the image is only 200 x 130).

I would love to include under every Thumbnail the JPG name (ie 001.jpg or just 001)

Is there an easy way to do this with Print Command? Any help

Please

Cheers

EDIT: Just added the code [br] & '. $file . ' after the Image & it works... (Great) Hope can I remove the .jpg though?
Say Image are 0001_thumbnail.jpg & I want to REMOVE _thumbnail.jpg off every image?

punky · 24-08-2010, 20:01

You can do a str_replace('_thumbnail.jpg', '',$string)

funkyCable · 24-08-2010, 22:10

HI Not sure if you seen this CMS but give it a try if you looking for an image gally. google Zenphoto. its a free php/mysql image gallery.

JediMaster · 25-08-2010, 16:10

Quote:

Originally Posted by punky

You can do a str_replace('_thumbnail.jpg', '',$string)

Sorry is this what you mean?

$jpg = str_replace('_thumbnail.jpg', '',$string);

Then where I want the Filenames I enter the command '. $jpg . '

**Graham M** · 25-08-2010, 16:38

Yes correct;

$jpg = str_replace('_thumbnail.jpg', '',$jpg);

str_replace returns a string, the above code would take .jpg and remove any instances of _thumbnail.jpg in the string variable "JPG"

JediMaster · 25-08-2010, 17:06

This is my CODE...

JPGs are inside my img/ folder (they Load Fine)
The Filenames dont show at all.

Code:

<?php

$jpg = str_replace('_thumbnail.jpg', '',$string);

$images = "img/"; # Location of small versions
$big    = "img/"; # Location of big versions (assumed to be a subdir of above)
$cols   = 4; # Number of columns to display

if ($handle = opendir($images)) {
   while (false !== ($file = readdir($handle))) {
       if ($file != "." && $file != ".." && $file != rtrim($big,"/")) {
           $files[] = $file;
       }
   }
   closedir($handle);
}

$colCtr = 0;

echo '<table width="100%" cellspacing="0" cellpadding="0"><tr>';

foreach($files as $file)
{
  if($colCtr %$cols == 0)
  echo '</tr><tr><td colspan="2"></td></tr><tr>';
  echo '<td align="center"><img src="' . $images . $file . '" /><br> '. $jpg . '</td>';

  $colCtr++;
}

echo '</table>' . "\r\n";

?>

**Graham M** · 25-08-2010, 17:13

Well where you've put that line of code, no variable $jpg has been used or initialised

Try

foreach($files as $file)
{
$fullname = str_replace('_thumbnail.jpg', '',$file);

if($colCtr %$cols == 0)
echo '</tr><tr><td colspan="2"></td></tr><tr>';
echo '<td align="center"><img src="' . $images . $file . '" /><br> '. $fullname . '</td>';

$colCtr++;
}

JediMaster · 25-08-2010, 18:10

Hi Graham. Now page wont load...

Code:

<?php

foreach($files as $file)
{
$fullname = str_replace('_thumbnail.jpg', '',$file);

$images = "img/"; # Location of small versions
$big    = "img/"; # Location of big versions (assumed to be a subdir of above)
$cols   = 4; # Number of columns to display

if ($handle = opendir($images)) {
   while (false !== ($file = readdir($handle))) {
       if ($file != "." && $file != ".." && $file != rtrim($big,"/")) {
           $files[] = $file;
       }
   }
   closedir($handle);
}

$colCtr = 0;

echo '<table width="100%" cellspacing="0" cellpadding="0"><tr>';

foreach($files as $file)
{
  if($colCtr %$cols == 0)
  echo '</tr><tr><td colspan="2"></td></tr><tr>';
  echo '<td align="center"><img src="' . $images . $file . '" /><br> '. $fullname  . '</td>';

  $colCtr++;
}

echo '</table>' . "\r\n";

?>

**Graham M** · 25-08-2010, 18:20

Errr... I replaced part of your code, didn't tell you to add it, have you tried reading what you've put?

JediMaster · 26-08-2010, 09:17

Quote:

Originally Posted by Graham M

Errr... I replaced part of your code, didn't tell you to add it, have you tried reading what you've put?

Totally lost me sorry...

Can you explain??

Oops I see... I added the line of code in wrong place :P

Works GREAT Now Cheers

JediMaster · 12-10-2010, 16:37

Is there a way to list the files in Alphabetical Order ? It seams random at the moment?

Cheers

**Graham M** · 12-10-2010, 17:09

RTFM

http://php.net/manual/en/function.sort.php

You need to do that on the $files array, give it a go and come back if you're stuck still

JediMaster · 12-10-2010, 17:41

Hi Graham M. No idea what or where needs editing? I'm new to PHP. Any advice (or answers) would be grateful

So far my code is:

Code:

<?php

$images = "tn_/"; # Location of small versions
$big    = "img/"; # Location of big versions (assumed to be a subdir of above)
$cols   = 4; # Number of columns to display

if ($handle = opendir($images)) {
   while (false !== ($file = readdir($handle))) {
       if ($file != "." && $file != ".." && $file != rtrim($big,"/")) {
           $files[] = $file;
       }
   }
   closedir($handle);
}

$colCtr = 0;


echo '<table width="100%" cellspacing="0" cellpadding="0"><tr>';

foreach($files as $file)
{ $fullname = str_replace('.jpg', '',$file);
  if($colCtr %$cols == 0)
  echo '</tr><tr><td colspan="2"></td></tr><tr>';
  echo '<td align="center"><a rel="thumbnail" href="' . $big . $file . '"><img src="' . $images . $file . '" /></a><b><font size="2" face="Arial" color="#000000"><br><a href="http://www.domain.com">View</a><br>ID Code: <font color="#FF0000">'. $fullname  . '</font><br><br></font></b></td>';

  $colCtr++;
}

echo '</table>' . "\r\n";

?>

**Graham M** · 12-10-2010, 18:15

Well you'll never learn unless you play about with it yourself

Anyhow, the following should help.

Just above the line

PHP Code:


			
foreach ($files as $file)

Add a new line

PHP Code:


			
sort($files);

No need to self reference this one in the return as it works directly on the array and returns true or false depending on if it's worked

**Graham M** · 13-10-2010, 00:02

So did this do what you wanted?